Maths

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Across
  1. 1. x∈H∩K
  2. 4. if |H|=10 and |K|=21
  3. 5. group 1 is identity e
  4. 6. x∈H then,we have 0(x)|10 implies that 0(x)=1,2,5 or 10
  5. 7. needed to prove that if |H|=10 and|k|=21,then H∩K={e}
Down
  1. 1. H and K be subgroup of G where e is the identity of G
  2. 2. ,we have x∈H or x∈K
  3. 3. H∩K=1=e
  4. 5. x∈K,then we have0(x)|2|