Across
- 1. x∈H∩K
- 4. if |H|=10 and |K|=21
- 5. group 1 is identity e
- 6. x∈H then,we have 0(x)|10 implies that 0(x)=1,2,5 or 10
- 7. needed to prove that if |H|=10 and|k|=21,then H∩K={e}
Down
- 1. H and K be subgroup of G where e is the identity of G
- 2. ,we have x∈H or x∈K
- 3. H∩K=1=e
- 5. x∈K,then we have0(x)|2|